Find the roots of the quadratic equation by applying the quadratic formula:
$2 x^{2} + x - 4 = 0$

(N/A) Given equation: $2 x^{2} + x - 4 = 0$
On comparing this equation with the standard form $a x^{2} + b x + c = 0$,we obtain:
$a = 2, b = 1, c = -4$
By using the quadratic formula,$x = \frac{-b \pm \sqrt{b^{2} - 4 a c}}{2 a}$:
Substituting the values:
$x = \frac{-1 \pm \sqrt{(1)^{2} - 4(2)(-4)}}{2(2)}$
$x = \frac{-1 \pm \sqrt{1 + 32}}{4}$
$x = \frac{-1 \pm \sqrt{33}}{4}$
Thus,the roots are $x = \frac{-1 + \sqrt{33}}{4}$ and $x = \frac{-1 - \sqrt{33}}{4}$.